34.I
for this problem you just multiply the 20 by 2=40
and then you add 40+3=43
which will equal
[tex] \frac{43}{20} [/tex]
35.G
if you divide
[tex]58 \div 25 = 2.32[/tex]
so G
[tex] \frac{58}{25} [/tex]
36. C
[tex]\frac{5}{5} = 1[/tex]
so if you subtract
[tex] \frac{6}{5} - \frac{5}{5} [/tex]
will equal
[tex] \frac{1}{5} [/tex]
[tex]1 \frac{1}{5} [/tex]
