At noon, ship a is 50 km west of ship
b. ship a is sailing south at 10 km/h and ship b is sailing north at 20 km/h. how fast is the distance between the ships changing at 4:00 pm? (round your answer to one decimal place.) 23.05 incorrect: your answer is incorrect. km/h
Given: dA/dt=10 km/hr and dB/dt=20 km/hr bade of the triangle is 50 km we are required to find dD/dt when t=4 hr (A+B)^2+50^2=D^2
d/dt((A+B)^2+50^2)=d/dt(D^2) [d(A+B)]/dt2(A+B)(2)=dD/dt2D A=10km/hr*4hr=40 km B=20km/hr*4hr=80 km (10+20)*(2)*(120)*(2)=2*√8000*dD/dt dD/dt=7200/sqrt(8000) 80.5 km/hr
