SnoopWhoElse
SnoopWhoElse SnoopWhoElse
  • 13-01-2016
  • Chemistry
contestada

How many moles of hexane (C6H14) must burn to form 18.4 mol of carbon dioxide?

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Willchemistry
Willchemistry Willchemistry
  • 13-01-2016
The combustion reaction of hexane:

2 C6H14 + 19 O2 = 12 CO2 + 14 H2O

2 mol C6H14 ---------> 12 mol CO2
x mol C6H14 ---------> 18.4 mol CO2

12 * x = 18.4 * 2

12 x = 36.8

x = 36.8 / 12

x = 3.067 moles of CO2

hope this helps!.
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peanutbutter20
peanutbutter20 peanutbutter20
  • 13-02-2020

Answer: C. 3.07 moles

Explanation:

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