KayDelane KayDelane
  • 12-01-2018
  • Mathematics
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How do you factor— 27x^3-8

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altavistard
altavistard altavistard
  • 12-01-2018
Recognize that there are several cubes here.

27x^3-8 = 3^3*x^3 - 2^3, which is the same as (3x)^3 - 2^3

This latter result is the difference of cubes, and thus it can be factored further as follows:

[ (3x) - 2 ][(3x)^2 + 6x + 4] 

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