marie138 marie138
  • 12-11-2017
  • Mathematics
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Given that (x+2) is a factor of x^3+8, find the other quadratic factor.

Given that x2 is a factor of x38 find the other quadratic factor class=

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KitKat69
KitKat69 KitKat69
  • 12-11-2017
The difference of two cubes: a^3+b^3= (a+b)(a^2-ab+b^2)
So we have x^3+8 = (X+2)(x^2-2x+4)
square the first
Multiply the first and second
square the second
Notice that the sign in front of the middle term is opposite that of the first factor, if it wasn't the problem wouldn't work :)
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