Respuesta :

the 1 / y^-2  =  1 / 1 / y^2  = y2
so the expression becomes (x^-3 y^2)^-1   the -1 outside the  parentheses = 1/ what s inside so we get
  1 / (y^2 x^-3)   =  x^3/y^2   or  x^3 y^-2
y^2/x^3 or y^2 over x^3