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  • 10-04-2017
  • Mathematics
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Find a value of k such that kx^2 + 12x − 4 = 0 has one real-number solution. Explain.

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iiAgneez
iiAgneez iiAgneez
  • 10-04-2017
For one and only 1 real solution, the discriminant = 0 (see chart attached) 
So we know b^2-4ac=0 when the equation is in the format of ax^2+bx-c=0. Make sure your equation is in the right format first!

Given kx^2+12x-4=0 
b=12 
so b^2-4ac=0 
144 = 4ac 
144 = 4(k)(-4) 
144/(-16) = k 
k = -9
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