kieranherr kieranherr
  • 10-04-2017
  • Mathematics
contestada

How do i solve this? [tex]sec^2x+2secx[/tex]

Respuesta :

Аноним Аноним
  • 10-04-2017
sec x = a

sec^2 x + 2sec x = 0

a^2 + 2a = 0

a(a + 2) = 0

a = 0 or a + 2 = 0

a = -2

i.e. sec x = -2
1/cos x = -2
-2cos x = 1
cos x = -1/2

Hope I helped!
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