Given
Mass of the shot, M=50 kg
Its speeed, u=35 m/s
Mass of the smaller shots, m=m'=25 kg
let its velocity be v
To find
The velocity of the smaller shots
Explanation
By conservation of momentum,
[tex]\begin{gathered} Mu=(m+m^{\prime})v \\ \Rightarrow50\times35=(25+25)v \\ \Rightarrow v=\frac{50\times35}{(25+25)} \\ \Rightarrow v=\frac{50\times35}{50} \\ \Rightarrow v=35\text{ m/s} \end{gathered}[/tex]
Conclusion
The velocity is 35 m/s.
