RuteRod
RuteRod
11-02-2017
Mathematics
contestada
How would you solve this problem?
Respuesta :
geerky42
geerky42
11-02-2017
Square both sides:
2s + 8 = s²
0 = s² - 2s - 8
Now factor:
0 = (s-4)(s+2)
s - 4 = 0 OR s + 2 = 0
s = 4 OR s = -2
Since square root cannot be negative, s = -2 is not possible,
so we are left with
s = 4
Answer Link
miner3mj
miner3mj
11-02-2017
Square both sides to find 2s +8 = s^2 and then subtract so it would be s^2 -2s -8 = 0. Then you factor to get (s-4)(s+2)=0 and get s={-2,4} then you check for answers that are extraneous and find that -2 is an extraneous answer which means s=4
Answer Link
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