Answer:
88 square units
Step-by-step explanation:
Area of trapezium
a and b are the length of the parallel sides.
a = IL = 15
b = JK = 7
h = height between the parallel lines = 8
[tex]\sf \boxed{\bf Area \ of \ trapezium = \dfrac{(a +b)*h}{2}}[/tex]
[tex]\sf =\dfrac{(15+7)*8}{2}\\\\=\dfrac{22*8}{2}\\\\= 11*8\\\\= 88 \ square \ units[/tex]
