Answer:
for example okk then you will try
Answer: (1) (2 – e2)3/2
Solution:
Given,
tan2θ = 1 – e2
sec θ + tan3θ cosec θ
= sec θ + (sin3θ/cos3θ) (1/sin θ)
= sec θ + tan2θ sec θ
= sec θ(1 + tan2θ)
= √(1 + tan2θ) (1 + tan2θ)
= (1 + tan2θ)3/2
= (1 + 1 – e2)3/2
= (2 – e2)3/2
