Answer:
At the value of x = 3 the function H(x) is undefined. (answer is 3)
Step-by-step explanation:
h (x) = 1/(x-5)2 + 4 (x-5) +4
Solution :
We know that for the values of x where denominator is zero the function H(x) is not define.
(x -5)2 +4 (x -5 ) +4 = 0
x2 -6x +9 =0
x2 - 3x - 3x +9 = 0
(x - 3)2 = 0
So x= 3
At x = 3 the function H(x) is undefined. (3 is your answer)
