9514 1404 393
Answer:
13
Step-by-step explanation:
152AB1 is not a square in hexadecimal, so we assume A and B are supposed to represent single digits in decimal.
If A=B=0, √152001 ≈ 389.9
If A=B=9, √152991 ≈ 391.1
The least significant digit of 152AB1 being non-zero, we know it is not the square of 390. Hence, it must be the square of 391.
For 152AB1 to be a perfect square, we must have ...
152AB1 = 391² = 152881
The sum of the digits of the square root is 3+9+1 = 13.
