a line contains the points (4,2) and (0,-1). what is the equation of the line. a) y=2x -6
b)y= 3/4x -1
c) y= 1/4x + 1
d) y= 4/3x - 10/3

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10-12-2016
Mathematics

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a line contains the points (4,2) and (0,-1). what is the equation of the line. a) y=2x -6
b)y= 3/4x -1
c) y= 1/4x + 1
d) y= 4/3x - 10/3

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sihangu sihangu · Answer 1 · 2016-12-10T16:47:48+01:00

sihangu sihangu

10-12-2016

To do this, we should calculate the gradient first
m=y2-y1 overx2-x1
m=-1-2 over 0-4
m=-3 over -4
m=3 over 4

formula of a straight is y-y1=m(x-x1)
y-2=3/4x-3
y=3/4x-1

so the answer is b)

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a line contains the points (4,2) and (0,-1). what is the equation of the line. a) y=2x -6 b)y= 3/4x -1 c) y= 1/4x + 1 d) y= 4/3x - 10/3

Respuesta :

Otras preguntas

a line contains the points (4,2) and (0,-1). what is the equation of the line. a) y=2x -6
b)y= 3/4x -1
c) y= 1/4x + 1
d) y= 4/3x - 10/3