linvillehannah21
linvillehannah21 linvillehannah21
  • 11-03-2021
  • Biology
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A man with homzy type A blood and a woman with heterozygous type B blood want to know the probability of having a child with type AB blood.

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Phobic111
Phobic111 Phobic111
  • 11-03-2021

Answer:

[tex]\frac{1}{2}[/tex]

Explanation:

Homzy. type A blood = AA

Heterozygous type B blood = Bb

Punnett square

     |  B   |  b  

  A | AB | Ab

  A | AB | Ab

The ratio is = 2:2 = 1 : 1

The total number of outcomes are 4

The number of AB are 2

Thus the probability is [tex]\frac{2}{4} = \frac{1}{2}[/tex]

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