adamsalehadoomygang
adamsalehadoomygang adamsalehadoomygang
  • 12-12-2020
  • Mathematics
contestada

in a science experiment, mark had to record the change in the height of a can

Respuesta :

LynxVillicana
LynxVillicana LynxVillicana
  • 12-12-2020

Answer:

[tex]\frac{dr}{dt\\}[/tex] = ([tex]\frac{dV}{dT}[/tex]/π - r²[tex]\frac{dh}{dt\\}[/tex])/2h

Step-by-step explanation:

V = πr²h

[tex]\frac{dV}{dT}[/tex]= π(r²[tex]\frac{dh}{dt\\}[/tex]+2h[tex]\frac{dr}{dt\\}[/tex])

[tex]\frac{dV}{dT}[/tex]/π= r²[tex]\frac{dh}{dt\\}[/tex]+2h[tex]\frac{dr}{dt\\}[/tex]

([tex]\frac{dV}{dT}[/tex]/π - r²[tex]\frac{dh}{dt\\}[/tex])/2h = [tex]\frac{dr}{dt\\}[/tex]

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