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  • 10-10-2016
  • Mathematics
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x^4-1 divided by x^2-1

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  • 10-10-2016
   
[tex]\displaystyle \\ \frac{x^4-1}{x^2-1} = \frac{(x^2+1)(x^2-1)}{x^2-1} = \boxed{x^2+1}[/tex]



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