Answer:
D'(-2, -1)
E'(5, 5)
Step-by-step explanation:
DE has the coordinates of the endpoints as D(-3, -4) and E(4, 2).
These points are translated by the rule to give the translated image as D'E',
(x, y) → (x + 1, y + 3)
By following this rule,
D(-3, -4) → D'(-3 + 1, -4 + 3)
→ D'(-2, -1)
E(4, 2) → E'(4 + 1, 2 + 3)
→ E'(5, 5)
Now we can graph these image points having coordinates D'(-2, -1) and E'(5, 5).
