leonelgutierrez630 leonelgutierrez630

11-07-2020
Mathematics

contestada

Find the values of a, b, and c in the equation
below.
(x^5yz^4)^3/x^3yz=x^ay^bz^c

Respuesta :

ronhagrid310 ronhagrid310

11-07-2020

Answer:

a = 12, b = 2, z = 11

Step-by-step explanation:

(x^5yz^4)^3/(x^3yz)

= (x^15y^3z^12)/(x^3yz)

= x^12y^2z^11

=> a = 12

=> b = 2

=> z = 11

Answer Link

Dududhdjufjfnf Dududhdjufjfnf

02-03-2021

Answer:

a=12

b=2

z=11

Step-by-step explanation:

I got it right

Answer Link

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