Answer:
A. 80.0microColoumbs
B.120.0 microcoloumbs
C.37.3v
Explanation:
See attached file
a. The charge Q1 on capacitor C1 should be 80.0 μC.
b. The charge on capacitor C3 should be 120 μC.
c. The applied voltage should be 37.5 v.
a. We know that
v = q/c
Q1/c1 = Q2/C2
Q1 = (C1/C2) Q2
= (6.00/3.00) * 40
= 80.0
b.
Q3 = Q1 + Q2
= (80 + 40)
= 120
c.
The voltage should be
= 80/ 6+ 120/5
= 37.5 V
hence,
a. The charge Q1 on capacitor C1 should be 80.0 μC.
b. The charge on capacitor C3 should be 120 μC.
c. The applied voltage should be 37.5 v.
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