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11-06-2020
Chemistry

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calculate the ph of a solution containing 0.001 mol dm-3 Naoh

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11-06-2020

Answer:

pOH = - log [molarity of OH-] = - log [ molarity of NaOH] , assuming full dissociation. Thus, pOH = - log ( 0.001) = - (-3) = 3. Thus, the pH of 0.001 mol/dm3 NaOH solution is 11.

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