Answer:
3[tex]\sqrt{141}[/tex]
Step-by-step explanation:
Use the Pythagorean Theorem.
[tex]37^{2}[/tex]=[tex]x^{2}[/tex]+[tex]10^{2}[/tex]
1369=[tex]x^{2}[/tex]+100
-100 -100
1269=[tex]x^{2}[/tex]
[tex]\sqrt{1269}[/tex]=[tex]\sqrt{x^{2} }[/tex]
3[tex]\sqrt{141}[/tex]=x
