Respuesta :

rabinshrestha41
[tex] \frac{v-9}{10v} +6=11[/tex]

Subtracting 6 on both sides, we get,

[tex] \frac{v-9}{10v} =11-6[/tex]

[tex] \frac{v-9}{10v} =5[/tex]

Multiplying by 10v on both sides , we get,

[tex] \frac{v-9}{10v}*10v =5 *10v[/tex]

[tex]v-9=50v[/tex]

[tex]-9 = 50v -v[/tex]

[tex]-9=49v[/tex]

[tex] \frac{-9}{49} =v[/tex]

[tex]v=- \frac{9}{49} [/tex]
mariamikayla
[tex]\frac{v-9}{10v+6}=11 \\\\ 11(10v+6)=v-9 \\\\ 110v+66=v-9 \\\\ 110v-v=-9-66 \\\\ 109v= -75 \\\\ \boxed{v=-\frac{75}{109}}[/tex]

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