Respuesta :

konrad509
[tex]1+2+3+4+\ldots+99+100=\\ (1+100)+(2+99)+(3+98)+\ldots(50+51)=\\ 50\cdot101=\\ 5050[/tex]
You can use Gauss method...

Sum from 1 to n = [n(n+1)] / 2

So... 1 to 100 = [100(100+1)] / 2

= [100(101)] / 2
= [10100] / 2
= 5050

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