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  • 10-10-2019
  • Mathematics
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through point (0, 10) and PERPENDICULAR to the line through (-2, -9) and (-4, -17)?

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LammettHash
LammettHash LammettHash
  • 10-10-2019

Compute the slope of the line through (-2, -9) and (-4, -17):

[tex]\dfrac{-9-(-17)}{-2-(-4)}=\dfrac82=4[/tex]

Any line perpendicular to this line will have slope -1/4. The one that passes through (0, 10) satisifes

[tex]y-10=-\dfrac14(x-0)\implies\boxed{y=10-\dfrac x4}[/tex]

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