Answer:
C
Step-by-step explanation:
So I'm going to subtract (x+7)/(x+3) on both sides:
(x-6)/(x+5)-(x+7)/(x+3)>=0
Now I'm going to find a common denominator which is (x+5)(x+3).
[(x-6)(x+3)-(x+7)(x+5)]/[(x+5)(x+3)]>=0
Now I just have a lot of simplifying to do:
[x^2+3x-6x-18-(x^2+5x+7x+35)]/(x^2+3x+5x+15)>=0
[-3x-18-12x-35]/(x^2+8x+15)>=0
[-15x-53]/[x^2+8x+15]>=0
