andoniaresti andoniaresti

10-06-2019
Mathematics

contestada

Find 3 numbers in a geometrical sequence if:

a1+a2+a3=21
a1xa2xa3=64 (That x is multiplying)

Respuesta :

BILALGREAT BILALGREAT

10-06-2019

a1+a2+a3=21

(a1=1,a2=3,a3=7)

a1xa2xa3=64

(a1=2,a2=4,a3=8)

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