[tex]\dfrac{5}{3}=\dfrac{s}{t}\qquad\text{cross multiply}\\\\5t=3s\qquad\text{divide both sides by 5}\cdot3\\\\\dfrac{5\!\!\!\!\diagup^1 t}{5\!\!\!\!\diagup_1\cdot3}=\dfrac{3\!\!\!\!\diagup^1s}{5\cdot3\!\!\!\!\diagup_1}\\\\\dfrac{t}{3}=\dfrac{s}{5}[/tex]
