Hello from MrBillDoesMath!
Answer: 23
Steps:
Let "n" be the smallest integer in the set of 5 consecutive integer. Then
n + (n+1) + (n+2) + (n+3) + (n+4) = 110.
Simplifying gives
5n + (1 + 2 +3 +4) = 110 or
5n + 10 = 110. Subtracting 10 from each side gives
5n= 110-10 = 100
So n = 20, and the fourth number in the (n+3) or 20+3 or 23
Regards, MrB
