prestonhayes7884 prestonhayes7884
  • 10-07-2018
  • Mathematics
contestada

Find the area of the parallelogram that has adjacent sides u = i-3j+2k and v = 3j-k

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sqdancefan
sqdancefan sqdancefan
  • 10-07-2018
The area is the given by the magnitude of the cross product of the side vectors. That value is
  Area = ||u×v|| = ||u||·||v||·sin(θ)
where θ is the angle between the vectors.

The cross product of [1, -3, 2] and [0, 3, -1] is [-3, 1, 3}, which has magnitude
  √((-3)² +1² +3²) = √19 ≈ 4.3589
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