Seudónimo Seudónimo
  • 11-05-2018
  • Mathematics
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Simplify completely 12 times x to the third power minus 4 times x to the 2nd power plus 8 times x all over negative 2 times x.

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Аноним Аноним
  • 11-05-2018
[tex] \dfrac{12x^3-4x^2 + 8x}{-2x} [/tex]

[tex]= \dfrac{-2x(6x^2+ 2x - 4)}{-2x} [/tex]

[tex]= 6x^2+ 2x - 4 [/tex]

[tex]= 2(3x - 2)(x + 1)[/tex]
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