Choose the equation of a line in standard form that satisfies the given conditions. perpendicular to 4x + y = 8 through (4, 3) A. x − 4y = −8 B. x + 4y = 16 C. 4x − y = 11 D. 4x + y = 19
we have that Choose the equation of a line in standard form that satisfies the given conditions. perpendicular to 4x + y = 8 through (4, 3)
4x + y = 8-----> y=-4x+8-----> the slope m is -4
we know that if two lines are perpendicular then m1*m2=-1 m1=-4 so m2=1/4
with m=1/4 and point (4,3) find the equation of the line y=mx+b 3=(1/4)*4+b-----> 3=1+b-----> b=2 y=(1/4)*x+2------> (1/4)*x-y=-2-----> multiply by 4----> x-4y=-8
